2x^2-19x+48=0

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Solution for 2x^2-19x+48=0 equation:


Simplifying
2x2 + -19x + 48 = 0

Reorder the terms:
48 + -19x + 2x2 = 0

Solving
48 + -19x + 2x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
24 + -9.5x + x2 = 0

Move the constant term to the right:

Add '-24' to each side of the equation.
24 + -9.5x + -24 + x2 = 0 + -24

Reorder the terms:
24 + -24 + -9.5x + x2 = 0 + -24

Combine like terms: 24 + -24 = 0
0 + -9.5x + x2 = 0 + -24
-9.5x + x2 = 0 + -24

Combine like terms: 0 + -24 = -24
-9.5x + x2 = -24

The x term is -9.5x.  Take half its coefficient (-4.75).
Square it (22.5625) and add it to both sides.

Add '22.5625' to each side of the equation.
-9.5x + 22.5625 + x2 = -24 + 22.5625

Reorder the terms:
22.5625 + -9.5x + x2 = -24 + 22.5625

Combine like terms: -24 + 22.5625 = -1.4375
22.5625 + -9.5x + x2 = -1.4375

Factor a perfect square on the left side:
(x + -4.75)(x + -4.75) = -1.4375

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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